Question

Сократите дроби пожалуйста!:1.а)-8x/40xy
б)3a^2/12a
в)3x^5y/12x^3y^3
2.а)3x+6b/6(x+2b)
б)c^2-12c+36/3c-18
в)3y^2+12y/y^2-16
3.а)3b/12xb
б)5a^2/20a
в)x^6y^2/x^4y^3
4.а)2x+2b/6(x+b)
б)a^2-10a+25/6a-30
в)4y-32/y^2-64

Answer 1

1) а)$\frac{-8x}{40xy} = -\frac{1}{5y}$
б) $\frac{3a^{2}}{12a}= \frac{a}{4}$
в) $\frac{3x^{5}y}{12x^{3}y^{3}}= \frac{x^{2}}{4y^{2}}$
2) а) $\frac{3x+6b}{6(x+2b)}= \frac{3(x+2b)}{6(x+2b)}= \frac{1}{2}$
б) $\frac{c^{2}-12c+36}{3c-18}= \frac{(c-6)^{2}}{3(c-6)}= \frac{c-6}{3}$
в) $\frac{3y^{2}+12y}{y^{2}-16}= \frac{3y(y+4)}{(y-4)(y+4)}= \frac{3y}{y-4}$
3) а) $\frac{3b}{12bx}= \frac{1}{4x}$
б) $\frac{5a^{2}}{20a} = \frac{a}{4}$
в) $\frac{x^{6}y^{2}}{x^{4}y^{3}}= \frac{x^{2}}{y}$
4) a) $\frac{2x+2b}{6(x+b)}= \frac{2(x+b)}{6(x+b)}= \frac{1}{3}$
б) $\frac{a^{2}-10a+25}{6a-30} = \frac{(a-5)^{2}}{6(a-5)}= \frac{a-5}{6}$
в) $\frac{4y-32}{y^{2}-64}= \frac{4(y-8)}{(y-8)(y+8)}= \frac{4}{y+8}$