Question

помогите пожалуйста!!!!!!!!

Answer 1

!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

$\frac{8ab }{a+8b} * ( \frac{a}{8b} - \frac{8b}{a} ) = \frac{8ab }{a+8b} * \frac{a*a-8b*8b}{8ab} = \frac{8ab}{a+8b} * \frac{a^2-(8b)^2}{8ab} = \\ \\ = \frac{8ab * (a-8b)(a+8b)}{(a+8b)*8ab} = \frac{1*(a-8b)*1}{1*1} = a - 8b$

при а =8√3 + 7 ;  b = √3 - 3
8√3 + 7 - 8(√3  - 3) = 8√3  + 7  - 8√3 - 8 *(-3) =  (8√3 - 8√3) + (7 + 24) = 31