Question

Задания 32 и 33 . напишите и формулы.

Answer 1

32
(cos1/x)`=-sin1/x *(-1/x2)=1/x²*sin1/x
ответ А
33
(sin1/x)`=cos1/x*(-1/x²)=-1/x²*sicos1/x
ответ A

Answer 2

$y_1=cos(\frac{1}{x} )\\y=cos(x)\\y'=-sin(x)*x'=\ \textgreater \ y_1'=-sin(\frac{1}{x} )*(\frac{1}{x} )'\\y_1'=-sin(\frac{1}{x} )*\frac{1'x-1x'}{x^2} =-sin(\frac{1}{x} )*\frac{-1}{x^2} =\frac{1}{x^2} sin(\frac{1}{x} )\\.............................................\\y_1=sin(\frac{1}{x} )\\y=sin(x)\\y'=cos(x)*x'=\ \textgreater \ y_1'=cos(\frac{1}{x} )*(\frac{1}{x} )'\\y_1'=-\frac{1}{x^2} cos(\frac{1}{x})$