Question

Помогите решить x^2-4x+3>или =0

Answer 1

$x^2-4x+3 \geq 0 \\ \\ (x-1)(x-3) \geq 0$

$\left \{\begin{array}{ccc}(x-1)\ \geq \ 0\\(x-3)\ \geq \ 0\end{array}\right \\ \\ \\ \left \{\begin{array}{ccc}x\ \geq \ 1\\x\ \geq \ 3\end{array}\right \ \Rightarrow x\ \geq \ 3$

или

$\left \{\begin{array}{ccc}(x-1) \leq 0\\(x-3) \leq 0\end{array}\right \\ \\ \\ \left \{\begin{array}{ccc}x \leq 1\\x \leq 3\end{array}\right \ \Rightarrow x \leq 1$


Ответ: 
$x \leq 1 \ \ \cup \ \ x \geq 3$