Question

решите нервенство:
х-8
₋₋₋ > 0
x+3

Answer 1

$\frac{x-8}{x+3} \ \textgreater \ 0 \\ (x-8)(x+3)\ \textgreater \ 0 \\ x_1 = 8 \ ; \ x_2=-3 \\ x \in (-\infty;-3) \cup (8;+\infty)$