Question

Срочно! Сократи дробь. 3m^2-3n^2: 3m-2mn+3n-2m^2

Answer 1

$\frac{3m^2-3n^2}{3m-2mn+3n-2m^2} = \frac{3(m^2-n^2)}{3m+3n-2mn-2m^2} = \frac{3(m-n)(m+n)}{3(m+n)-2m(n+m)} = \\ = \frac{3(m-n)(m+n)}{(m+n)(3-2m)} = \frac{3(m-n)}{3-2m}$