Question

Укажите область определения функции $y=\frac{x}{ \sqrt[4]{ 3x^{2}+2x-5 } }$

Answer 1

$3x^2+2x-5\ \textgreater \ 0 \\ \\ D=4+4*3*5=64=8^2 \\ \\ x_{1} =(-2+8)/6=1 \\ \\ x_{2} =(-2-8)/6=-10/6=-5/3 \\ \\ +++++(-5/3)-----(1)++++++$

x∈(-∞;-5/3)U(1;+∞)