Question

Задание 1:
\frac{0,4 * (0,5-0,4-0,375)}{(3,03*\frac{3}{8}-4\frac{1}{5}*\frac{5}{7})*\frac{11}{127}}=
Задание 2:
1) -6(1 - в) - 2(3 + 2в) + 12
2) \frac{4}{9}*(27m-\frac{9}{4}n)-42*(\frac{5}{7}m-0.5n)=
Задание 3:
1) 3\frac{1}{2}(3x+1)=0.5(1-3x)
2) 4+5x=16x-0.4+3(2-x)

Answer 1

1.$\frac{0,4 * (0,5-0,4-0,375)}{(3,03*\frac{3}{8}-4\frac{1}{5}*\frac{5}{7})*\frac{11}{127}}= \frac{0,4*(-0,275)}{ (\frac{909}{800}-3)* \frac{11}{127} }$
$\frac{0,4*(-0,275)}{ (\frac{909}{800}-3)* \frac{11}{127} } = \frac{1016}{1491}$
2. 1)$-6(1 - b) - 2(3 + 2b) + 12=-6+b-6-4b+12=-3b$
2)$\frac{4}{9}*(27m-\frac{9}{4}n)-42*(\frac{5}{7}m-0.5n)=12m-n-30m+21n=$
$=20n-18m$
3. 1) $3\frac{1}{2}(3x+1)=0.5(1-3x)$
$\frac{21}{2} x+ \frac{7}{2} =0.5-1.5x$
$10.5x+3.5=0.5-1.5x$
$12x=-3$
$x= -\frac{1}{4}$
2) $4+5x=16x-0.4+3(2-x)$
$4+5x=16x-0.4+6-3x$
$5x-16x+3x=5.6-4$
$-8x=1.6$
$x=-0.2$