Question

25x^2-36>0
решите неравенства

Answer 1

$25x^2-36 \ \textgreater \ 0 \\ (5x-6)(5x+6)\ \textgreater \ 0 \\ x_1 =-1 \frac{1}{5} \ ; \ x_2 = 1 \frac{1}{5} \\ x \in (-\infty;-1 \frac{1}{5}) \cup ( 1\frac{1}{5};+\infty)$