Question

Решите уравнение!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

$\frac{x^2-2x+1}{x-3} + \frac{x+1}{3-x} = 4 \\ \frac{x^2-2x+1}{x-3} - \frac{x+1}{x-3} =4 \\ x^2-2x+1-x-1=4x-12 \\ x^2-7x+12=0 \\ D = 49 - 48 = 1 \\ x_{1,2} = \frac{7 \ \pm \ 1}{2} = \left \{ {{x_1=3} \atop {x_2=4}} \right.$