Question

Решите (3x^2y^4/4m^3)^2. (-10m^2/3n^2р^3)^3

Answer 1

$( \frac{3x^2y^4}{4m^3} )^2 = \frac{3^{1*2} *x^{2*2} *y^{4*2}}{4^{1*2} *m^{3*2}} = \frac{3^2x^4y^8}{4^2m^6} = \frac{9x^4y^8}{16m^6}$

$( \frac{-10m^2}{3n^2p^3} )^3= \frac{(-10)^{1*3} *m^{2*3}}{3^{1*3} *n^{2*3} *p^{3*3}} = \frac{(-10)^3*m^6}{3^3*n^6*p^9} = \frac{-1000m^6}{27n^6p^9} = - \frac{1000m^6}{27n^6p^9}$