Question

помогите прошу вас - умоляю

Answer 1

$\frac{y^2-6y+9}{y^2-9}:\frac{10y-30}{y^2+3y}=\frac{(y-3)^2}{(y-3)(y+3)}\cdot \frac{y(y+3)}{10(y-3)}=\frac{y}{10}= \frac{70}{10}=7$

Answer 2

$=\frac{( y-3 )^{2} }{(y-3)(y+3)}* \frac{y(y+3)}{10*(y-3)} = \frac{y}{10}$ , при y=70 
70/10=7
Ответ 7