Question

log 0.25 (3) / 3 log 2 (27)

Answer 1

перейдем к основанию 10
$\frac{ log_{0,25} 3}{3 log_{2}27 } = \frac{ lg3 }{ lg0.25} : \frac{3lg27}{ lg2 } =\frac{ lg3 }{ lg\frac{1}{4} }* \frac{lg2}{9lg3} = \frac{1}{lg 2^{-2} } * \frac{lg2}{9} =- \frac{1}{18}$

Answer 2

log 0.25 (3) / 3 log 2 (27)=log(3)3/log(3)0,25:3 log(3)27/log(3)2=
=1/-2log(3)2*log(3)2/9=-1/2*1/9=-1/18