Question

помогите пожалуйста.
там
lim
x->3/8

Answer 1

$\lim_{x \to \frac{3}{8} } (\frac{6}{(8x-3)(8x+3)} - \frac{1}{8x-3} )= \lim_{x \to \frac{3}{8} } \frac{6-8x-3}{(8x-3)(8x+3)} =\\= \lim_{x \to \frac{3}{8} } \frac{-(8x-3)}{(8x-3)(8x+3)} = \lim_{x \to \frac{3}{8} } \frac{-1}{8x+3} =- \frac{1}{6}$