Question

x⁴-4x²+3=0 ................

Answer 1

Замена х^2=у
${y}^{2} - 4y + 3 = 0 \\ po \: teoreme \: vietta \\ y1 = 1 \: \: \: \: \: \: \: \: y2 = 3 \\ {x}^{2} = 1 \ \: \: \: \: \: \: \: \: {x}^{2} = 3 \\ x = + - 1 \: \: \: \: \: \: \: x = + - \sqrt{3}$