Question

пОМОГИТЕ ПОЖАЛУЙСТА 1 ЗАДАНИЦЕ

Answer 1

$\left \{ {{x+xy-3y=-3} \atop {2x-xy+y=2}} \right. \\\\ \left \{ {{x+xy-3y+2x-xy+y=-3+2} \atop {x+xy-3y=-3}} \right. \\\\ \left \{ {{3x-2y=-1} \atop {3x+3x*y-9y=-9}} \right. \\\\ \left \{ {{3x=2y-1} \atop {2y-1+(2y-1)*y-9y=-9}} \right. \\\\ \left \{ {{3x=2y-1} \atop {2y-1+2y^2-y-9y=-9}} \right. \\\\ \left \{ {{3x=2y-1} \atop {2y^2-8y+8=0}} \right. \\\\ \left \{ {{3x=2y-1} \atop {y^2-4y+4=0}} \right. \\\\ \left \{ {{x=\frac{2y-1}{3}} \atop {(y-2)^2=0}} \right.$

$\left \{ {{x=\frac{2y-1}{3}} \atop {y-2=0}} \right. \\\\ \left \{ {{x=\frac{2*2-1}{3}} \atop {y=2}} \right. \\\\ \left \{ {{x=1}} \atop {y=2}} \right.$

Ответ: $(1;\ 2)$