Question

6m-4(mm)²| mn²=?
При m= одна целая одна четвертая
При n= одна целая одна восьмая

Answer 1

$6m - \frac{4(mm)^2}{mn^2} = 6m - \frac{4(m^2)^2}{mn^2} = 6m - \frac{4m^4}{m^1*n^2} = 6m- \frac{4m^3}{n^2} =\\ \\ \\ m= 1 \frac{1}{4} = \frac{5}{4} ; n= 1 \frac{1}{8} = \frac{9}{8} \\ \\ 6 * \frac{5}{4} - \frac{4 * ( \frac{5}{4})^3 }{( \frac{9}{8})^2 } = \frac{15}{2} - \frac{ \frac{125}{16} }{\frac{81}{64} } = \frac{15}{2} - \frac{125*64}{16*81} = \frac{15}{2} - \frac{500}{81} = \\ \\ = \frac{1215 - 1000}{162} = \frac{215}{162} = 1 \frac{53}{162}$

Если в выражении опечатка:
$6m - \frac{4(mn)^2}{mn^2}= 6m - \frac{4m^2n^2}{mn^2} = 6m - \frac{4m}{1} = 6m-4m = 2m \\ \\ m= 1 \frac{1}{4} = \frac{5}{4} ; n= 1 \frac{1}{8} \\ \\ 2 * \frac{5}{4} = \frac{2*5}{1*4} = \frac{5}{2} = 2.5$