Question

Решить систему уравнений
{3(2х+у-1)=5х+4у+2
{ 4(х+2у+1)=2х-5у+6

Answer 1

{3(2х+у-1) = 5х+4у+2
{4(х+2у+1) = 2х-5у+6

{6х+3у-3 = 5х+4у+2
{4х+8у+4 = 2х-5у+6

{6х+3у-3-5х-4у-2 = 0
{4х+8у+4-2х+5у-6 = 0

{х-у-5 = 0 | х - у = 5 | х = 5 + у
{2х+13у-2 = 0
2(5+у) + 13у - 2 = 0
10+2у+13у-2 = 0
15у+8 = 0
15у = -8
у = -8/15
х = 4 7/15
Ответ: (-8/15; 4 7/15)