Question

Помогите ПОЖАЛУЙСТА. ОЧЕНЬ СРОЧНО.

Answer 1

$\left \{ {{\frac{x-2}{4-x}\ \textgreater \ 0} \atop {lg(\frac{x-2}{4-x}) \neq 0}} \right. \\\\ \left \{ {{\frac{x-2}{x-4}\ \textless \ 0} \atop {\frac{x-2}{4-x} \neq 1}} \right. \\\\ \left \{ {{x\in(2;\ 4)} \atop {\frac{2x-6}{x-4} \neq 0}} \right. \\\\ \left \{ {{x\in(2;\ 4)} \atop {x \neq 3}} \right. \\\\ x\in(2;\ 3)\cup(3;\ 4)$

Ответ: $D(y):=(2;\ 3)\cup(3;\ 4)$