Question

СРОЧНО ПОМОГИТЕ ПРОШУ!!!!!!!!!!!!!!!!!!!!!!
Найдите значение выражения y²-6y+9\y²-9 : 10y-30\y²+3y при y=70

Answer 1

$\frac{y^{2}-6y+9}{ y^{2} -9} : \frac{10y-30}{ y^{2} +3y} = \frac{(y-3)(y-3)}{(y-3)(y+3)} * \frac{y(y+3)}{10(y-3)} = \frac{y}{10}$

при  у=70
70:10=7

Answer 2

$\frac{ y^{2} -6y+9}{ y^{2}-9 } : \frac{10y-30}{ y^{2}+3y } = \frac{(y-3) ^{2} }{(y-3)(y+3)} * \frac{y(y+3)}{10(y-3)} = \frac{(y-3)*y*(y+3)}{(y+3)(y-3)*10} =[tex] \frac{y}{10} = \frac{70}{10}=7$