Question

номер 19 с решением пожалуйста

Answer 1

$\displaystyle 1)..\sqrt{150}+ \sqrt{600}- \sqrt{24}= \sqrt{25*6}+ \sqrt{100*6}- \sqrt{4*6}= \\ \\ =5 \sqrt{6}+10 \sqrt{6}-2 \sqrt{6}=13 \sqrt{6}; \\ \\ \\ 2).. \sqrt{125}-2 \sqrt{5}-1,2 \sqrt{20}= \sqrt{25*5}-2 \sqrt{5}-1,2 \sqrt{4*5}= \\ \\ =5 \sqrt{5}-2 \sqrt{5}-2,4 \sqrt{5}=0,6 \sqrt{5}= \sqrt{1,8}; \\ \\ \\ 3)..2 \sqrt{18}- \sqrt{8}+ \sqrt{128}=2 \sqrt{9*2}- \sqrt{4*2}+ \sqrt{64*2}= \\ \\ =6 \sqrt{2}-2 \sqrt{2}+8 \sqrt{2}=12 \sqrt{2};$


$\displaystyle 4).. \sqrt{98}+1,5 \sqrt{72}+ \sqrt{8}= \sqrt{49*2}+1,5 \sqrt{36*2}+ \sqrt{4*2}= \\ \\ =7 \sqrt{2}+9 \sqrt{2}+2 \sqrt{2}=18 \sqrt{2}; \\ \\ \\ 5).. \sqrt{27}-0,5 \sqrt{75}-2 \sqrt{48}= \sqrt{9*3}-0,5 \sqrt{25*3}-2 \sqrt{16*3}= \\ \\ =3 \sqrt{3}-2,5 \sqrt{3}-8 \sqrt{3}=-7,5 \sqrt{3}; \\ \\ \\ 6).. \sqrt{28}+2 \sqrt{63}-2,5 \sqrt{252}= \sqrt{4*7}+2 \sqrt{9*7}-2,5 \sqrt{36*7}= \\ \\ =2 \sqrt{7}+6 \sqrt{7}-15 \sqrt{7}=-7 \sqrt{7}$