Question

Пожалуйста помогите, очень срочно!!!!

Answer 1

$\frac{ {36}^{2k + 2} }{ {3}^{4k + 3} \times {4}^{2k + 2} } = \frac{{(9 \times 4)}^{2k + 2} }{{3}^{4k + 3} \times {4}^{2k + 2}} = \\ = \frac{{ {9}^{2k + 2} \times 4}^{2k + 2} }{{3}^{4k + 3} \times {4}^{2k + 2}} = \frac{ {9}^{2k + 2} }{ {3}^{4k + 3} } = \\ = \frac{ {( {3}^{2}) }^{2k + 2} }{ {3}^{4k + 3} } = \frac{ {3}^{4k + 4} }{ {3}^{4k + 3} } = \\ = \frac{ {3}^{4k} \times {3}^{4} }{ {3}^{4k} \times {3}^{3} } = \frac{ {3}^{4} }{ {3}^{3} } = 3$