Question

sin4π-sin*3π/2+cos3π
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cos8π

Answer 1

sin4p=2sin2p*cos2p=2*0*1=0

sin3p/2= -1

cos3p=4cos³p-3cosp=4*(-1)³-3*(-1)=-4+3=-1

cos8p=1-2sin²4p = 1-2*0²=1-0=1

[ 0-(-1)+(-1) ] / 1= 1-1=0