Question

решите неравенство (x-5)^2/x^2+6x-7 меньше или равно 0

Answer 1

$\frac{(x - 5) ^{2} }{ x^{2} +6x-7} \leq 0\\\\ \frac{(x-5) ^{2} }{(x+7)(x-1)} \leq 0$
Заменим частное произведением:
(x - 5)²(x + 7)(x - 1) ≤ 0
               +                            -                             +                        +
_______________₀_______________₀__________________________
                            - 7                                    1                   5
                              //////////////////////////////
x ∈ (- 7 ; 1)