Question

помогите решить 3tg^2 П\6 - cos^2 П\3 - cos^2 П\6

Answer 1

$3tg ^{2} \frac{ \pi }{6} -Cos ^{2} \frac{ \pi }{3} -Cos ^{2} \frac{ \pi }{6}=3*( \frac{1}{ \sqrt{3} } ) ^{2} -( \frac{1}{2}) ^{2}-( \frac{ \sqrt{3} }{2}) ^{2} =3* \frac{1}{3}- \frac{1}{4}- \frac{3}{4} =$$=1- 1 = 0$