Question

(2х-1)*2=4х*2-4х+1 решить

Answer 1

$(2x-1)^2=4x^2-4x+1\\\\ (2x-1)^2=(2x)^2-2*2x*1+1^2\\\\ (2x-1)^2=(2x-1)^2\\\\ 0*x=0\\\\ x\in(-\infty;\ +\infty)$

Альтернатива:
$(2x-1)^2=4x^2-4x+1\\\\ (2x)^2-2*2x*1+1^1=4x^2-4x+1\\\\ 4x^2-4x+1=4x^2-4x+1\\\\ 4x^2-4x^2-4x+4x+1-1=0\\\\ 0*x^2+0*x+0=0\\\\ 0*x=0\\\\ x\in(-\infty;\ +\infty)$

Ответ: $(-\infty;\ +\infty)$