Question

Решите неравенства:
4ˣ ≥ 3ˣ

Answer 1

$4^x\geq 3^x \bigg| :3^x>0\\ \bigg(\frac{4}{3}\bigg)^x\geq 1\\ y=\bigg(\frac{4}{3}\bigg)^x \; \; vozrastaet, t.k. \; \frac{4}{3} >1 => \\ znak \;\; ne\;\; menyaetsya=>\\ \bigg(\frac{4}{3}\bigg)^x\geq \frac{4}{3}^0\\ x\geq0\\ x \in [0; +\infty)$