Question

Решите пожалуйста 2 задания

Answer 1

$\frac{3x-0.1}{0.3}= \frac{20}{3}$
  3(3x-0.1) = 20*0.3
9x-0.3 = 6
9x = 6.3
x = 0.7

$\frac{0.5+x+ \frac{1}{3}-x+ \frac{1}{6} }{ \frac{1}{8}-y+0.25+y+ \frac{3}{} }$
$\frac{ \frac{5}{6} }{ \frac{15}{8} } = \frac{5*8}{6*15} = 40/90 = 4/9$