Question

Решите неравенства
(2-х)х
_______>=0
Х-3

Answer 1

$\frac{(2-x)x}{x-3} \geq 0, x \neq 3$
$\left \{ {{x*(2-x) \geq 0} \atop {x-3\ \textgreater \ 0}} \right.$
$\left \{ {{x*(2-x) \leq 0} \atop {x-3\ \textless \ 0}} \right.$
x ∈ ∅
x ∈ (-∞;0] ∪ [2;3)

Ответ: x ∈ (-∞;0] ∪ [2;3)