Question

Срочняк!
4 x (в квадрате) +11 х - 3 = 0

Answer 1

$= 4 {x}^{2} + 11x - 3 = 0 \\ d = 121 + 48 = 169 \\ x1 = \frac{ - 11 + 13}{8} = \frac{2}{8} = \frac{1}{4} = 0.25 \\ x2 = \frac{ - 11 - 13}{8} = - \frac{24}{8} = - 3$

Answer 2

$4x^2+11x-3=0 \\ D = 121 + 48 = 169 \\ x_{1,2} = \frac{-11\ \pm \13}{8} = \left \{ {{x_1=-3} \atop {x_2=0,25}} \right.$