Question

Найти интеграл dx/x^2

Answer 1

$\int\limits { \frac{1}{ x^{2} }} \, dx = \int\limits { {x^{-2} }} \, dx = -1 * x^{-1} = - \frac{1}{x}+C$

Answer 2

$\int \frac{1}{x^2}dx = \int x^{-2}dx=\frac{x^{-2+1}}{-2+1}+C=-\frac{1}{x} + C$