Question

ПОМОГИТЕ ПОЖАЛУЙСТА
х²-12/x²-4 + x/x-2 = 1

Answer 1

(х²-12)/(х²-4) + х/(х-2) = 1,
(х²-12)/(х-2)(х+2) + х/(х-2) = 1,
(х²-12)/(х-2)(х+2) + х(х+2)/(х+2)(х-2) = (х+2)(х-2)/(х+2)(х-2),
(х²-12 + х²+2х)/(х+2)(х-2) = (х²-4)/(х+2)(х-2),
х²-12+х²+2х-х²+4 = 0,
х² + 2х - 8 = 0,
Д = 2² - 4*1*(-8) = 4 + 32 = 36,
х1 = (-2 + 6)/2*1 = 4/2 = 2,
х2 = (-2 - 6)/2*1 = -8/2 = -4,

х+2 ≠ 0,   х-2 ≠ 0,
х ≠ -2,      х ≠ 2,

ответ:  х = -4

Answer 2

(x²-12):(x²-4)+x:(x-2)=1
(x²-12):(x²-4)+x:(x-2)=1
x²-12/x²-4+x/x-2=1
x²-12/(x-2)*(x+2)+x/x-2=1
x²-12+x*(x+2)/(x+2)*(x-2)=1
x²-12+x²+2x/(x+2)*(x-2)=1
2x²-12+2x/(x+*(x-2)=1
2(x*(x+3)-2(x+3))/(x+2)*(x-2)=1
2(x+3)/x+2=1
2x+6=x+2
2x-x=2-6
x=-4,