Question

1000^(x+2) * 0.001=2^(x^2-1) * 5^(x^2-1)

Answer 1

1000^(x+2) * 0.001=2^(x^2-1) * 5^(x^2-1)

(10^3)^(x+2) *10^(-3)=(2*5)^(x^2-1)

10^(3x+6) *10^(-3)=10^(x^2-1)

10^(3x+6-3)=10^(x^2-1)

10^(3x+3)=10^(x^2-1)

3x+3=x^2-1

x^2-3x-1-3=0

x^2-3x-4=0

(x-4)(x+1)=0

x-4=0 или х+1=0

х=4 или х=-1