Question

Вычислить
1)tg45°+ctg²30°cos45°
2)sin60°+sin²45°

Answer 1

$tg45 ^{o} + Ctg ^{2}30 ^{o}Cos ^{2} 45 ^{o}=1+( \sqrt{3} ) ^{2}* (\frac{ 1 }{ \sqrt{2} }) ^{2} =1+3* \frac{1}{2}=1+1,5=2,5\\\\Sin60 ^{o}+Sin ^{2}45 ^{o} = \frac{1}{2}+( \frac{1}{ \sqrt{2} }) ^{2}= \frac{1}{2} + \frac{1}{2} =1$