Question

Помогите срочно нужно
16mx^2/3y^3÷(4m^3x)
-6xy^2/5ab÷(9x^2y^2/10ab)

Answer 1

$\frac{16m x^{2} }{3 y^{3} } * \frac{1}{4 m^{3}x } = \frac{4x}{3 y^{3} m^{2} }$
$- \frac{6x y^{2} }{5ab}* \frac{10ab}{9 x^{2} y^{2} } =- \frac{4}{3x}$