Question

подробно пожалуйста!!!

Answer 1

$\frac{3}{2+x} \ \textgreater \ 2\\\\ \frac{3}{2+x} -2\ \textgreater \ 0\\\\ \frac{3-4-2x}{2+x}\ \textgreater \ 0\\\\ \frac{-2x-1}{2+x} \ \textgreater \ 0\\\\ \frac{2x+1}{2+x} \ \textless \ 0$
Заменим частное произведением:
(2x + 1)(2 + x) < 0
2(x + 0,5)(x + 2) < 0
(x + 0,5)(x + 2) < 0
            +                           -                            +
_____________₀______________₀___________
                        - 2                         - 0,5
                          ///////////////////////////////
x ∈ (- 2 ; - 0,5)