Question

ПРОШУУУУУУУУУ ОЧЕНЬ СРОЧНО 3 И 4Й номер

Answer 1

номер 3:
а)
$\frac{{x}^{3} \times x }{( { {x}^{2} )}^{2} } = \frac{ {x}^{4} }{ {x}^{4} } = 1$
б)
${( - 0.4 {a}^{3} b)}^{2} = 0.16 {a}^{6} {b}^{2}$
в)
${( {m}^{3} \times {m}^{2} )}^{2} \times {(2m)}^{3} = \\ = {m}^{6} \times {m}^{4} \times 8 \times {m}^{3} = 8 {m}^{13}$
номер 4:
а)
$- 2x(1 - x) + (2x - 3)(x - 1) = \\ = - 2x + 2 {x}^{2} + 2 {x}^{2} - 2x - 3x + 3 = \\ = 4 {x}^{2} - 7x + 3 \\ x1 = \frac{7 + \sqrt{49 - 4 \times 4 \times 3} }{8} = 1 \\ x2 = \frac{7 - \sqrt{49 - 4 \times 4 \times 3} }{8} = \frac{6}{8} = \frac{2}{3}$
б)
$4 {(1 + 3x)}^{2} - 24x = 4(1 + 6x + 9 {x}^{2} ) - 24x = \\ = 4 + 24x + 36 {x}^{2} - 24x = 36 {x}^{2} + 4$
в)
$(x + 4)(x - 4) - {(x - 3)}^{2} = \\ = {x}^{2} - 16 -( {x}^{2} - 6x + 9) = \\ = {x}^{2} - 16 - {x}^{2} + 6x - 9 = \\ = 6x - 25$