Question

Найти производную функции y=(x+2) / (x^2-9)

Answer 1

$y' = \frac{(x+2)'(x^2-9)-(x+2)(x^2-9)'}{(x^2-9)^2} = \frac{x^2-9-2x^2-4x}{(x^2-9)^2} = \frac{-x^2-4x-9}{(x^2-9)^2}$

Answer 2

y = $\frac{x+2}{ x^{2} -9}$

y' = $\frac{ (x^{2} -9)- 2x(x+2)}{ (x^{2}-9) ^{2} }$

y' = $\frac{- x^{2} -4x - 9}{( x^{2}-9) ^{2} }$