Question

Решите пример,срочно

Answer 1

$\frac{x+2}{x(x+3)} - \frac{1+x}{(x-3)(x+3)} = \frac{(x+2)(x-3)-x(1+x)}{x(x^2-9)} =\\\\= \frac{x^2-x-6-x-x^2}{x(x^2-9)} = \frac{-2x-6}{x(x^2-9)} = \frac{-2(x+3)}{x(x-3)(x+3)} = -\frac{2}{x(x-3)}$