Question

9^3+x+3^2(x+1)=738*1/81

Answer 1

729+x+9(x+1)=738/81
729+x+9x+9=82/9
738+10x=82/9
10x= -6560/9
X= -656/9

Answer 2

$9^{3+x} + 3^{2*(x+1)} =738* \frac{1}{81}$
$(3^{2} ) ^{3+x} + 3^{2x+2} =738* \frac{1}{81}$
$3^{2x+6} + 3^{2x+2} =738* \frac{1}{81}$
$3^{2x+2}*( 3^{4}+1 )=738* \frac{1}{81}$
$3^{2x+2}*(81+1)=738* \frac{1}{81} | :82$
$3^{2x+2}= \frac{1}{9} 3^{2x+2}= 3^{-2}$

2x+2=-2
2x= - 4


x= - 2