Question

2*16^x-2^4x-4^2x-2=15

Answer 1

$2* 16^{x}- 2^{4x}- 4^{2x-2}=15 2* ( 2^{4} )^{x} - 2^{4x} - ( 2^{2} )^{2x-2} =15 2* 2^{4x} - 2^{4x} - 2^{4x-4} =15 2*2 ^{4x} -1* 2^{4x} - \frac{1}{ 2^{4} } * 2^{4x} =15 2^{4x}*(2-1- \frac{1}{16} ) =15$
$2^{4x}* \frac{15}{16} =15 |: \frac{15}{16} 2^{4x}=16 2^{4x} = 2^{4}$
4x=4

x=1