Question

помагите!!!!!!!!!!!!!!! С АЛГЕБРОЙ!
$\frac{32 + 14x - {x}^{2} }{ {x}^{2} - 4} = 0$

Answer 1

32+14x-$x^{2}$=0
$x^{2}$-14x-32=0
x1+x2=14   x1=-2
x1*x2=-32   x2=16
$x^{2}$-4$\neq$0
$x^{2} \neq 4$
x$\neq 2$   x