Question

$\frac{3x}{4x+4y} - \frac{6x}{8x+8y}$

Answer 1

$\frac{3x}{4x + 4y} - \frac{6x}{8x + 8y} = \frac{3x}{4(x + y)} - \frac{6x}{8(x + y)} = \frac{6x - 6x}{8(x + y)} = \frac{0}{8(x + y)} = 0$