Question

реши уравнения (64+×):12-11=43 ;(а-12 ):25-75=55;(7852:х++17898):40=455

Answer 1

1)(64+х)/12=43+11
(64+х)/12=54
64+х = 54*12
64+х = 648
х = 648-64=584


2)(а-12)/25=55+75
(а-12)/25=130
а-12 = 3250
а=3262


3) (7852/х+17898)=455*40
7852/х = 18200-17898=302
х = 7852/302 = 26