Question

Решите неравенства (х+3)(2х^2-7х+5)<0

Answer 1

(х+3)(2х^2-7х+5)<0

2х^2-7х+5=0    √D=√49-40=3   x1=1/4[7-3]=1   x2=1/4[7+3]=2.5

2х^2-7х+5=(x-1)(x-2.5)

(х+3)(x-1)(x-2.5)<0

-------------- -3--------------- 1-------------------- 2.5-----------------
      -                     +                          -                         +

x(-∞;-3)∪(1;2.5)