Question

Сократи дробь (x−3)^2/x^2+4x−21

Answer 1

(x−3)^2/x^2+4x−21     x^2+4x−21   x1=-7  x2=3

x^2+4x−21=(x+7)(x-3)    (x−3)^2/x^2+4x−21  = (x−3)^2/(x+7)(x-3)= (x−3)/(x+7)