Question

Решите пожалуста
(3х-2)(3х+2)=4х(х-1)

Answer 1

$(3x-2)(3x+2)=4x(x-1) \\ (3x)^2-2^2=4x^2-4x \\ 9x^2-4=4x^2-4x \\ 9x^2-4-4x^2+4x=0 \\ 5x^2+4x-4=0 \\ D = b^2-4ac = 16 + 80 = 96 \\ x_1 = \frac{-4+ \sqrt{96} }{10} = \frac{-4+ 4\sqrt{6}}{10} = \frac{4( \sqrt{6}-1)}{10} = \frac{2( \sqrt{6} -1)}{5} \\ x_2 = \frac{-4- \sqrt{96} }{10} = \frac{-4- 4\sqrt{6}}{10} = \frac{4( -\sqrt{6}-1)}{10} = \frac{2( -\sqrt{6} -1)}{5}$