Question

$\frac{6 ^{4 n+4} 0.5 ^{-3-2n} }{72 ^{2 n+2} }$ 

Answer 1

$\mathtt{\frac{6^{4n+4}*(\frac{1}{2})^{-3-2n}}{72^{2n+2}}=\frac{36^{2n+2}*2^{2n+3}}{72^{2n+2}}=\frac{36^{2n+2}*2^{2n+3}}{36^{2n+2}*2^{2n+2}}=2^{2n+3-(2n+2)}=2}$