Question

3x^2+x-2>=0

решить неравенство

Answer 1

$3x^2+x-2 \geq 0 \\ D=1+4*3*2=25 \\ x_{1} =-1+5/6=4/6=2/3 \\ x_{2} =-1-5/6=-6/6=-1 \\ 3(x-2/3)(x-1) \geq 0 \\ (3x-2)(x-1) \geq 0$
-------+---------2/3-----_-----------1-------+----
Ответ: x ⊂ (-∞;2/3] ∪ [1;+∞)