Question

-4/3x^2+12=0
Pomogite pls:)

Answer 1

$- \frac{4}{3} x^2+12=0 \ | \ *3 \\ \\ - 4x^2+36=0 \\ \\ 4 x^{2} =36 \\ \\ x^{2} = 9 \\ \\ x_{1,2} = \pm 3$

Ответ: 
$x_{1,2} = \pm 3$